Simplify directions response

openrouteservice directions
1

Hello there,
since there is no matrix API for public transport yet, I wanted to do it the “manual” way, by just using the direcitons api. This works quite well, but since I want to make a large amount of requests, I am thinking of optimizing.

At the moment, I am making this request:

    url = f"{base_url}/v2/directions/public-transport"

    # ORS erwartet Koordinaten in [lon, lat] Format
    coordinates = [[source['lon'], source['lat']], [target['lon'], target['lat']]]
    body = {
        "coordinates": coordinates,
        "preference": costing_options.get("preference", "RECOMMENDED").lower(),
        "units": "m",
        "language": "de",
        "geometry": False,
        "instructions": False,
        "arrival": departure_time,
        "maneuvers": False
    }

which already removes a lot.

In my response, I still have the legs and meta information though. Is it possible to remove or simplify them?
Or are there other parameters, that I could tweak to increase the performance?

Kind regards

2

Hey,

apart from "geometry": False which you are already using, there is nothing that will improve the query performance.

You can thus use post-processing on the response to remove leg and meta information, if you don’t need it, but that is not something the openrouteservice provides.

Best regards